log1p
result = log1p(x)
Input: x · Output: result
What it is
ln(1 + x), computed so it stays accurate for x near zero (log1p(1e-15) does not underflow to exactly 0, unlike naively computing 1.0 + x first). x is a scalar, Vec, or Mat/Signal.
Overloads
One call shape — this function is not overloaded.
| Code | Input | Output | Description |
result = log1p(x) | x scalar, Vec, Mat, or Signalnot documented yet | result — | Returns exactly the same type and shape as x. |
Examples
No documentation example calls this form yet. The Core maths chapter is where one belongs.