after_last

Builtin index · Collections & strings

result = after_last(s, mark)

Input: s, mark · Output: result

What it is

s/mark are Strs.

Overloads

One call shape — this function is not overloaded.

Examples

From the documentation, and run by the build -- the output and the figure below are what the engine actually produced. Simplest first.

path = "report_final_v2.txt"
print(ends_with(path, ".txt"))         # true

print(index_of(path, "_"))              # 6

print(last_index_of(path, "_"))         # 12

print(insert("helloworld", 5, ", "))    # "hello, world"

print(remove("hello, world", ", "))     # "helloworld"

line = "key: value"
print(after(line, ": "))                # "value"

print(before(line, ": "))               # "key"

full = "a/b/c.txt"
print(after_last(full, "/"))            # "c.txt"

print(before_last(full, "/"))           # "a/b"

true
6
12
hello, world
helloworld
value
key
c.txt
a/b

from collections-strings

How it works

after(s, mark) / before(s, mark) — the piece past, or up to, a marker. Written as a pair because they chain: s.after("BEGIN").before("END") is the whole idiom, and it reads in the order the text does. A marker that is not there yields the WHOLE string rather than an error or an empty one. before on a line with no comment marker should be the line; after on a header that never appeared should be the body you were handed. An empty result would silently discard the text.

From the note above this builtin in the interpreter, where the reasoning was written down as it was built.

See also

before_last — documented in the same entry.